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Solutions question

2021 · 27 Aug · Shift 1 · Q16
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Solutions question

2021 · 27 Aug · Shift 1 · Q16

JEE MainChemistrySolutionsNumerical+4 / −1
1 kg of 0.75 molal aqueous solution of sucrose can be cooled up to −-− 4 ∘^\circ∘ C before freezing. The amount of ice (in g) that will be separated out is ‾\underline{\hspace{2cm}}​. (Nearest integer) [Given : Kf(H2OH_2OH2​O) = 1.86 K kg mol −-− 1]
Numerical answer
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