JEE MainChemistrySalt AnalysisMCQ+4 / −1
Match the LIST-I with LIST-II
| LIST-I (Reagent) | LIST-II (Functional Group detected) |
|---|---|
| A. Sodium bicarbonate solution | I. double bond/unsaturation |
| B. Neutral ferric chloride | II. carboxylic acid |
| C. ceric ammonium nitrate | III. phenolic - OH |
| D. alkaline 4 | IV. alcoholic - OH |
Choose the correct answer from the options given below:
- AA-II, B-III, C-I, D-IV
- BA-II, B-IV, C-III, D-I
- CA-III, B-II, C-IV, D-I
- DA-II, B-III, C-IV, D-I
View written solutionFree
Correct answer: D
-
We match each reagent with the functional group it detects.
-
A. Sodium bicarbonate solution
- Carboxylic acids react with to release gas.
- Reaction:
- So, A II (carboxylic acid).
-
B. Neutral ferric chloride
- Neutral gives a colored complex with phenols.
- Hence, B III (phenolic ).
-
C. Ceric ammonium nitrate
- Ceric ammonium nitrate test is used for alcohols.
- Alcohols give a red/orange coloration.
- Therefore, C IV (alcoholic ).
-
D. Alkaline
- Alkaline potassium permanganate is Baeyer's reagent, used to detect unsaturation such as double bond.
- Thus, D I (double bond/unsaturation).
-
Final matching:
-
Compare with options:
- Option D:
So, the correct option is D.
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