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Salt Analysis question

2025 · 2 Apr · Shift 1 · Q6
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  5. /2025 · 2 Apr · Shift 1 · Q6

Salt Analysis question

2025 · 2 Apr · Shift 1 · Q6

JEE MainChemistrySalt AnalysisMCQ+4 / −1
Choose the correct tests with respective observations. (A) CuSO4\mathrm{CuSO}_4CuSO4​(acidified with acetic acid) +K4[Fe(CN)6]→+\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \rightarrow+K4​[Fe(CN)6​]→ Chocolate brown precipitate. (B) FeCl3+K4[Fe(CN)6]→\mathrm{FeCl}_3+\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \rightarrowFeCl3​+K4​[Fe(CN)6​]→ Prussian blue precipitate. (C) ZnCl2+K4[Fe(CN)6]\mathrm{ZnCl}_2+\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]ZnCl2​+K4​[Fe(CN)6​], neutralised with NH4OH→\mathrm{NH}_4 \mathrm{OH} \rightarrowNH4​OH→ White or bluish white precipitate. (D) MgCl2+K4[Fe(CN)6]→\mathrm{MgCl}_2+\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \rightarrowMgCl2​+K4​[Fe(CN)6​]→ Blue precipitate. (E) BaCl2+K4[Fe(CN)6]\mathrm{BaCl}_2+\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]BaCl2​+K4​[Fe(CN)6​], neutralised with NaOH→\mathrm{NaOH} \rightarrowNaOH→ White precipitate. Choose the correct answer from the options given below :
  1. A
    A, D and E only
  2. B
    A, B and C only
  3. C
    B, D and E only
  4. D
    C, D and E only
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