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Ionic Equilibrium question

2025 · 22 Jan · Shift 2 · Q11

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JEE Main
Chemistry
Ionic Equilibrium
2025 · 22 Jan · Shift 2 · Q11

Ionic Equilibrium question

2025 · 22 Jan · Shift 2 · Q11

JEE MainChemistryIonic EquilibriumMCQ+4 / −1

The molar solubility(s) of zirconium phosphate with molecular formula

\left(\mathrm{Zr}^{4+}\right)_3\left(\mathrm{PO}_4^{3-}\right)_4

is given by relation :

A
$\left(\frac{\mathrm{K}_{\mathrm{sp}}}{5348}\right)^{\frac{1}{6}}$
B
$\left(\frac{\mathrm{K}_{\mathrm{sp}}}{8435}\right)^{\frac{1}{7}}$
C
$\left(\frac{K_{s p}}{6912}\right)^{\frac{1}{7}}$
D
$\left(\frac{\mathrm{K}_{\mathrm{sp}}}{9612}\right)^{\frac{1}{3}}$

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