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Ionic Equilibrium question

2020 · 7 Jan · Shift 2 · Q18
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Ionic Equilibrium question

2020 · 7 Jan · Shift 2 · Q18

JEE MainChemistryIonic EquilibriumNumerical+4 / −1
3 g of acetic acid is added to 250 mL of 0.1 M HCL and the solution made up to 500 mL. To 20 mL of this solutions 12{1 \over 2}21​ mL of 5 M NaOH is added. The pH of the solution is ‾\underline{\hspace{2cm}}​. [Given : pKa of acetic acid = 4.75, molar mass of acetic of acid = 60 g/mol, log 3 = 0.4771] Neglect any changes in volume.
Numerical answer
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