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Hydrocarbons question

2021 · 27 Jul · Shift 2 · Q12
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Hydrocarbons question

2021 · 27 Jul · Shift 2 · Q12

JEE MainChemistryHydrocarbonsMCQ+4 / −1
The correct sequence of correct reagents for the following transformation is : JEE Main 2021 (Online) 27th July Evening Shift Chemistry - Hydrocarbons Question 74 English
  1. A
    (i) FeFeFe, HClHClHCl (ii) Cl2Cl_2Cl2​, HClHClHCl (iii) NaNO2NaNO_2NaNO2​, HClHClHCl, 0 ∘^\circ∘ C (iv) H2OH_2OH2​O/H+H^+H+
  2. B
    (i) FeFeFe, HClHClHCl (ii) NaNO2NaNO_2NaNO2​, HClHClHCl, 0 ∘^\circ∘ C (iii) H2OH_2OH2​O/H+H^+H+ (iv) Cl2Cl_2Cl2​, FeCl3FeCl_3FeCl3​
  3. C
    (i) Cl2Cl_2Cl2​, FeCl3FeCl_3FeCl3​ (ii) FeFeFe, HClHClHCl (iii) NaNO2NaNO_2NaNO2​, HClHClHCl, 0 ∘^\circ∘ C (iv) H2OH_2OH2​O/H+H^+H+
  4. D
    (i) Cl2Cl_2Cl2​, FeCl3FeCl_3FeCl3​ (ii) NaNO2NaNO_2NaNO2​, HClHClHCl, 0 ∘^\circ∘ C (iii) FeFeFe, HClHClHCl (iv) H2OH_2OH2​O/H+H^+H+
View written solutionFree

Correct answer: C

  1. Identify the likely transformation sequence

    From the given reagents, the transformation clearly involves the standard aromatic conversion:

    Benzene→chlorobenzene→aniline→benzenediazonium chloride→phenol\text{Benzene} \rightarrow \text{chlorobenzene} \rightarrow \text{aniline} \rightarrow \text{benzenediazonium chloride} \rightarrow \text{phenol}Benzene→chlorobenzene→aniline→benzenediazonium chloride→phenol

    This is because:

    • Cl2/FeCl3Cl_2/FeCl_3Cl2​/FeCl3​ gives chlorination of benzene.
    • Fe/HClFe/HClFe/HCl is used in reduction of a nitro group to an amine, so this suggests the intermediate before this step must be a nitro compound.
    • NaNO2/HCl,0∘CNaNO_2/HCl, 0^\circ CNaNO2​/HCl,0∘C converts aniline to diazonium salt.
    • H2O/H+H_2O/H^+H2​O/H+ hydrolyzes diazonium salt to phenol.
  2. Check the logical order of reactions

    The only chemically meaningful sequence among the options is:

    • First, electrophilic chlorination: Benzene→Cl2/FeCl3chlorobenzene\text{Benzene} \xrightarrow{Cl_2/FeCl_3} \text{chlorobenzene}BenzeneCl2​/FeCl3​​chlorobenzene

    • Then (implied nitration if present in the scheme image), reduction of nitro group: chloronitrobenzene→Fe/HClchloroaniline\text{chloronitrobenzene} \xrightarrow{Fe/HCl} \text{chloroaniline}chloronitrobenzeneFe/HCl​chloroaniline

    • Diazotization: chloroaniline→NaNO2/HCl, 0∘Cchlorobenzenediazonium chloride\text{chloroaniline} \xrightarrow{NaNO_2/HCl,\ 0^\circ C} \text{chlorobenzenediazonium chloride}chloroanilineNaNO2​/HCl, 0∘C​chlorobenzenediazonium chloride

    • Hydrolysis: chlorobenzenediazonium chloride→H2O/H+chlorophenol\text{chlorobenzenediazonium chloride} \xrightarrow{H_2O/H^+} \text{chlorophenol}chlorobenzenediazonium chlorideH2​O/H+​chlorophenol

    Thus the order of the listed reagents must be:

    (i) Cl2,FeCl3(ii) Fe,HCl(iii) NaNO2,HCl,0∘C(iv) H2O/H+(i)\ Cl_2, FeCl_3 \quad (ii)\ Fe, HCl \quad (iii)\ NaNO_2, HCl, 0^\circ C \quad (iv)\ H_2O/H^+(i) Cl2​,FeCl3​(ii) Fe,HCl(iii) NaNO2​,HCl,0∘C(iv) H2​O/H+

  3. Evaluate options

    • A: Starts with Fe/HClFe/HClFe/HCl → impossible at the beginning unless a nitro group already exists.
    • B: Starts with Fe/HClFe/HClFe/HCl and puts chlorination at the end → incorrect order.
    • C: (i) Cl2,FeCl3→(ii) Fe,HCl→(iii) NaNO2,HCl,0∘C→(iv) H2O/H+(i)\ Cl_2, FeCl_3 \rightarrow (ii)\ Fe,HCl \rightarrow (iii)\ NaNO_2,HCl,0^\circ C \rightarrow (iv)\ H_2O/H^+(i) Cl2​,FeCl3​→(ii) Fe,HCl→(iii) NaNO2​,HCl,0∘C→(iv) H2​O/H+ This is chemically consistent.
    • D: Diazotization before reduction to amine → impossible.
  4. Correct answer

    C\boxed{\text{C}}C​

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