Doubts
Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents
Sign in to save progress →
Doubts
Sign in

Hydrocarbons question

2021 · 27 Jul · Shift 2 · Q12
Guest · try one question or challengeGuest · try one question or challenge
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /Hydrocarbons
  5. /2021 · 27 Jul · Shift 2 · Q12

Hydrocarbons question

2021 · 27 Jul · Shift 2 · Q12

JEE MainChemistryHydrocarbonsMCQ+4 / −1
The correct sequence of correct reagents for the following transformation is : JEE Main 2021 (Online) 27th July Evening Shift Chemistry - Hydrocarbons Question 74 English
  1. A
    (i) FeFeFe, HClHClHCl (ii) Cl2Cl_2Cl2​, HClHClHCl (iii) NaNO2NaNO_2NaNO2​, HClHClHCl, 0 ∘^\circ∘ C (iv) H2OH_2OH2​O/H+H^+H+
  2. B
    (i) FeFeFe, HClHClHCl (ii) NaNO2NaNO_2NaNO2​, HClHClHCl, 0 ∘^\circ∘ C (iii) H2OH_2OH2​O/H+H^+H+ (iv) Cl2Cl_2Cl2​, FeCl3FeCl_3FeCl3​
  3. C
    (i) Cl2Cl_2Cl2​, FeCl3FeCl_3FeCl3​ (ii) FeFeFe, HClHClHCl (iii) NaNO2NaNO_2NaNO2​, HClHClHCl, 0 ∘^\circ∘ C (iv) H2OH_2OH2​O/H+H^+H+
  4. D
    (i) Cl2Cl_2Cl2​, FeCl3FeCl_3FeCl3​ (ii) NaNO2NaNO_2NaNO2​, HClHClHCl, 0 ∘^\circ∘ C (iii) FeFeFe, HClHClHCl (iv) H2OH_2OH2​O/H+H^+H+
PreviousNext

More from Hydrocarbons

  • For the following sequence of reactions, the correct products are : Includes diagram2021 · MCQ
  • The major product in the following reaction is : Includes diagram2020 · MCQ
  • Which of the following compounds produces an optically inactive compound on hydrogenation?2020 · MCQ
  • The total number of monohalogenated organic products in the following (including stereoisomers) reaction is ​. Includes diagram2020 · Numerical
  • The minimum number of moles of O2​ required for complete combustion of 1 mole of propane and 2 moles of butane is ​.2020 · Numerical
  • The major product obtained from the following reaction is : Includes diagram2020 · MCQ
  • The major product of the following reaction is : Includes diagram2020 · MCQ
  • Consider the following reaction : (CH3​)3​CCH(OH)CH3​conc.H2​SO4​​(CH3​)2​CHCH(Br)CH3​alc.KOH​(CH3​)2​CHCH(Br)CH3​(CH3​)3​OΘK⊕​(CH3​)2​OH∣​C​−CH2​−CHOΔ​…2020 · MCQ