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Electrochemistry question

2020 · 8 Jan · Shift 1 · Q9
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Electrochemistry question

2020 · 8 Jan · Shift 1 · Q9

JEE MainChemistryElectrochemistryNumerical+4 / −1
What would be the electrode potential for the given half cell reaction at pH = 5? ‾\underline{\hspace{2cm}}​. 2H2OH_2OH2​O →\to→ O2O_2O2​ + 4HHH ⊕\oplus⊕ + 4e– ; Ered0E_{red}^0Ered0​ = 1.23 V (R = 8.314 J mol–1 K–1 ; Temp = 298 k; oxygen under std. atm. pressure of 1 bar)
Numerical answer
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