JEE MainChemistryElectrochemistryNumerical+4 / −1
What would be the electrode potential for the given half cell reaction at pH = 5? . 2 + 4 + 4e– ; = 1.23 V (R = 8.314 J mol–1 K–1 ; Temp = 298 k; oxygen under std. atm. pressure of 1 bar)
Numerical answer
More from Electrochemistry
- For an electrochemical cell (s) | (aq,1M)|| (aq,1M)|(s) the ratio when this cell attains equilibrium is . (Given…2020 · Numerical
- 108 g of silver (molar mass 108 g mol–1) is deposited at cathode from (aq) solution by a certain quantity of electricity. The volume (in L) of oxygen gas produced at 273 K and 1 bar pressure from water by the same quantity of…2020 · Numerical
- Given that ; The strongest oxidizing agent is :2019 · MCQ
- Calculate the standard cell potential in (V) of the cell in which following reaction takes place : (aq) + (aq) (aq) + (s) Given that 2019 · MCQ
- The standard Gibbs energy for the given cell reaction in kJ mol–1 at 298 K is : (s) + (aq) (aq) + (s), E° = 2 V at 298 K (Faraday's constant, F = 96000 C mol–1)2019 · MCQ
- A solution of is electrolysed between platinum electrodes using 0.1 Faraday electricity. How many mole of will be deposited at the cathode?2019 · MCQ
- The anodic half-cell of lead-acid battery is recharged using electricity of 0.05 Faraday. The amount of electrolyzed in g during the process is : (Molar mass of = 303 g mol 1)2019 · MCQ
- If the standard electrode potential for a cell is 2 V at 300 K, the equilibrium constant (K) for the reaction (s) + (aq) (aq) + (s) at 300 K is approximately, (R = 8 JK 1mol 1, F =…2019 · MCQ