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Coordination Compounds question

2024 · 5 Apr · Shift 1 · Q12
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  5. /2024 · 5 Apr · Shift 1 · Q12

Coordination Compounds question

2024 · 5 Apr · Shift 1 · Q12

JEE MainChemistryCoordination CompoundsMCQ+4 / −1
The correct order of ligands arranged in increasing field strength.
  1. A
    F−<Br−<I−<NH3\mathrm{F}^{-}\lt \mathrm{Br}^{-}\lt \mathrm{I}^{-}\lt \mathrm{NH}_3F−<Br−<I−<NH3​
  2. B
    H2O<−OH<CN−<NH3\mathrm{H}_2 \mathrm{O}\lt \mathrm{^{-}OH}\lt \mathrm{CN}^{-}\lt \mathrm{NH}_3H2​O<−OH<CN−<NH3​
  3. C
    Br−<F−<H2O<NH3\mathrm{Br}^{-}\lt \mathrm{F}^{-}\lt \mathrm{H}_2 \mathrm{O}\lt \mathrm{NH}_3Br−<F−<H2​O<NH3​
  4. D
    Cl−<−OH<Br−<CN−\mathrm{Cl}^{-}\lt \mathrm{^{-}OH}\lt \mathrm{Br}^{-}\lt \mathrm{CN}^{-}Cl−<−OH<Br−<CN−
View written solutionFree

Correct answer: C

  1. We need the order of ligands in increasing field strength.

  2. Use the spectrochemical series:

I−<Br−<Cl−<F−<OH−<H2O<NH3<CN−<⋯\mathrm{I^-} < \mathrm{Br^-} < \mathrm{Cl^-} < \mathrm{F^-} < \mathrm{OH^-} < \mathrm{H_2O} < \mathrm{NH_3} < \mathrm{CN^-} < \cdotsI−<Br−<Cl−<F−<OH−<H2​O<NH3​<CN−<⋯

This means ligand field strength increases from left to right.

  1. Now check each option.

Option A

F−<Br−<I−<NH3\mathrm{F^-} < \mathrm{Br^-} < \mathrm{I^-} < \mathrm{NH_3}F−<Br−<I−<NH3​

But actual order among these is:

I−<Br−<F−<NH3\mathrm{I^-} < \mathrm{Br^-} < \mathrm{F^-} < \mathrm{NH_3}I−<Br−<F−<NH3​

So A is incorrect.

Option B

H2O<OH−<CN−<NH3\mathrm{H_2O} < \mathrm{OH^-} < \mathrm{CN^-} < \mathrm{NH_3}H2​O<OH−<CN−<NH3​

Actual order is:

OH−<H2O<NH3<CN−\mathrm{OH^-} < \mathrm{H_2O} < \mathrm{NH_3} < \mathrm{CN^-}OH−<H2​O<NH3​<CN−

So B is incorrect.

Option C

Br−<F−<H2O<NH3\mathrm{Br^-} < \mathrm{F^-} < \mathrm{H_2O} < \mathrm{NH_3}Br−<F−<H2​O<NH3​

From the spectrochemical series:

Br−<F−<H2O<NH3\mathrm{Br^-} < \mathrm{F^-} < \mathrm{H_2O} < \mathrm{NH_3}Br−<F−<H2​O<NH3​

This matches exactly. So C is correct.

Option D

Cl−<OH−<Br−<CN−\mathrm{Cl^-} < \mathrm{OH^-} < \mathrm{Br^-} < \mathrm{CN^-}Cl−<OH−<Br−<CN−

Since

Br−<Cl−<OH−<CN−\mathrm{Br^-} < \mathrm{Cl^-} < \mathrm{OH^-} < \mathrm{CN^-}Br−<Cl−<OH−<CN−

this order is wrong. So D is incorrect.

  1. Therefore, the correct option is:
C\boxed{\text{C}}C​
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