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Coordination Compounds question

2019 · 11 Jan · Shift 1 · Q8
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Coordination Compounds question

2019 · 11 Jan · Shift 1 · Q8

JEE MainChemistryCoordination CompoundsMCQ+4 / −1
Match the metals (column I) with the coordination compound(s)/enzyme(s) (column II)

(Column I) Metals
 (Column II) Coordination
compounds(s) enzyme(s)
(A) Co (i) Wilkinson catalyst
(B) Zn (ii) Chlorophyl
(C) Rh (iii) Vitamin B12
(D) Mg (iv) Carbonic anhydrase
  1. A
    (A)-(iii); (B)-(iv); (C)-(i); (D)-(ii)
  2. B
    (A)-(iv); (B)-(iii); (C)-(i); (D)-(ii)
  3. C
    (A)-(i); (B)-(ii); (C)-(iii); (D)-(iv)
  4. D
    (A)-(ii); (B)-(i); (C)-(iv); (D)-(iii)
View written solutionFree

Correct answer: A

  1. We match each metal with the well-known coordination compound/enzyme containing it.

  2. Identify the metal present in each species:

    • Wilkinson catalyst is RhCl(PPh3)3\mathrm{RhCl(PPh_3)_3}RhCl(PPh3​)3​, so it contains Rhodium (Rh).

      Hence, Rh→Wilkinson catalyst  (i)\mathrm{Rh} \rightarrow \text{Wilkinson catalyst} \;(i)Rh→Wilkinson catalyst(i)

    • Chlorophyll contains Magnesium (Mg) at the center of the porphyrin-like ring.

      Hence, Mg→Chlorophyll  (ii)\mathrm{Mg} \rightarrow \text{Chlorophyll} \;(ii)Mg→Chlorophyll(ii)

    • **Vitamin B}_{12}$ is a cobalt complex (corrin ring complex of Co).

      Hence, Co→Vitamin B12  (iii)\mathrm{Co} \rightarrow \text{Vitamin B}_{12} \;(iii)Co→Vitamin B12​(iii)

    • Carbonic anhydrase is a zinc-containing enzyme.

      Hence, Zn→Carbonic anhydrase  (iv)\mathrm{Zn} \rightarrow \text{Carbonic anhydrase} \;(iv)Zn→Carbonic anhydrase(iv)

  3. Therefore the full matching is:

    • (A)(A)(A) Co →(iii)\rightarrow (iii)→(iii)
    • (B)(B)(B) Zn →(iv)\rightarrow (iv)→(iv)
    • (C)(C)(C) Rh →(i)\rightarrow (i)→(i)
    • (D)(D)(D) Mg →(ii)\rightarrow (ii)→(ii)

  4. Compare with options:

    Option A states: (A)−(iii); (B)−(iv); (C)−(i); (D)−(ii)(A)-(iii);\ (B)-(iv);\ (C)-(i);\ (D)-(ii)(A)−(iii); (B)−(iv); (C)−(i); (D)−(ii) which matches exactly.

Therefore, the correct answer is Option A.

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