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Compounds Containing Nitrogen question

2023 · 31 Jan · Shift 2 · Q4
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  5. /2023 · 31 Jan · Shift 2 · Q4

Compounds Containing Nitrogen question

2023 · 31 Jan · Shift 2 · Q4

JEE MainChemistryCompounds Containing NitrogenMCQ+4 / −1
An organic compound [A](C4H11 N)[\mathrm{A}]\left(\mathrm{C}_{4} \mathrm{H}_{11} \mathrm{~N}\right)[A](C4​H11​ N), shows optical activity and gives N2\mathrm{N}_{2}N2​ gas on treatment with HNO2\mathrm{HNO}_{2}HNO2​. The compound [A][\mathrm{A}][A] reacts with PhSO2Cl\mathrm{PhSO}_{2} \mathrm{Cl}PhSO2​Cl producing a compound which is soluble in KOH\mathrm{KOH}KOH. The structure of A\mathrm{A}A is :
  1. A
    JEE Main 2023 (Online) 31st January Evening Shift Chemistry - Compounds Containing Nitrogen Question 82 English Option 1
  2. B
    JEE Main 2023 (Online) 31st January Evening Shift Chemistry - Compounds Containing Nitrogen Question 82 English Option 2
  3. C
    JEE Main 2023 (Online) 31st January Evening Shift Chemistry - Compounds Containing Nitrogen Question 82 English Option 3
  4. D
    JEE Main 2023 (Online) 31st January Evening Shift Chemistry - Compounds Containing Nitrogen Question 82 English Option 4
View written solutionFree

Correct answer: B

  1. From reaction with HNO2\mathrm{HNO_2}HNO2​
    A primary aliphatic amine reacts with nitrous acid to give alcohol with evolution of nitrogen gas:
RNH2+HNO2→ROH+N2+H2O\mathrm{RNH_2 + HNO_2 \rightarrow ROH + N_2 + H_2O}RNH2​+HNO2​→ROH+N2​+H2​O

So, [A][A][A] must be a 1° amine.

  1. From Hinsberg test
    [A][A][A] reacts with PhSO2Cl\mathrm{PhSO_2Cl}PhSO2​Cl to give a product soluble in KOH\mathrm{KOH}KOH. This is characteristic of a primary amine, because the sulfonamide formed contains an acidic N–H and dissolves in alkali.

So again, [A][A][A] is confirmed as a primary amine.

  1. Molecular formula analysis
    Given formula is C4H11N\mathrm{C_4H_{11}N}C4​H11​N. Possible primary amines are:
  • butan-1-amine: CH3CH2CH2CH2NH2\mathrm{CH_3CH_2CH_2CH_2NH_2}CH3​CH2​CH2​CH2​NH2​
  • butan-2-amine: CH3CH(NH2)CH2CH3\mathrm{CH_3CH(NH_2)CH_2CH_3}CH3​CH(NH2​)CH2​CH3​
  • 2-methylpropan-1-amine: (CH3)2CHCH2NH2(\mathrm{CH_3})_2\mathrm{CHCH_2NH_2}(CH3​)2​CHCH2​NH2​
  • 2-methylpropan-2-amine: (CH3)3CNH2(\mathrm{CH_3})_3\mathrm{CNH_2}(CH3​)3​CNH2​
  1. Optical activity condition
    For optical activity, the molecule must contain a chiral carbon atom.
  • butan-1-amine: no chiral center
  • butan-2-amine: carbon-2 is attached to NH2\mathrm{NH_2}NH2​, H\mathrm{H}H, CH3\mathrm{CH_3}CH3​, and C2H5\mathrm{C_2H_5}C2​H5​ → four different groups, so chiral
  • 2-methylpropan-1-amine: no chiral center
  • 2-methylpropan-2-amine: central carbon has three identical CH3\mathrm{CH_3}CH3​ groups, so achiral

Thus, the only structure satisfying all conditions is:

CH3−CH(NH2)−CH2−CH3\mathrm{CH_3-CH(NH_2)-CH_2-CH_3}CH3​−CH(NH2​)−CH2​−CH3​

which is butan-2-amine (sec-butylamine).

  1. Comparison with stored answer
    Derived answer is Option B. This matches the stored correct answer.
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