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Compounds Containing Nitrogen question

2022 · 26 Jul · Shift 1 · Q13
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Compounds Containing Nitrogen question

2022 · 26 Jul · Shift 1 · Q13

JEE MainChemistryCompounds Containing NitrogenMCQ+4 / −1
The correct stability order of the following diazonium salt is JEE Main 2022 (Online) 26th July Morning Shift Chemistry - Compounds Containing Nitrogen Question 93 English
  1. A
    (A)>(B)>(C)>(D)(\mathrm{A})\gt (\mathrm{B})\gt (\mathrm{C})\gt (\mathrm{D})(A)>(B)>(C)>(D)
  2. B
    (A)>(C)>(D)>(B)(\mathrm{A})\gt (\mathrm{C})\gt (\mathrm{D})\gt (\mathrm{B})(A)>(C)>(D)>(B)
  3. C
    (C)>(A)>(D)>(B)(\mathrm{C})\gt (\mathrm{A})\gt (\mathrm{D})\gt (\mathrm{B})(C)>(A)>(D)>(B)
  4. D
    (C)>(D)>(B)>(A)(\mathrm{C})\gt (\mathrm{D})\gt (\mathrm{B})\gt (\mathrm{A})(C)>(D)>(B)>(A)
View written solutionFree

Correct answer: B

  1. Key idea: stability of diazonium salts

    Aryldiazonium salts are stabilized when the aryl ring can better accommodate the positive charge associated with the diazonium group, and when decomposition is less favored.

    In general:

    • Electron-withdrawing groups on the ring increase stability of diazonium salts.
    • Electron-donating groups decrease stability.
    • Substituent position also matters because of resonance and inductive effects.
  2. Compare the substituted diazonium salts

    From the given answer choices, the intended comparison corresponds to compounds A,B,C,DA, B, C, DA,B,C,D where one is most stabilized and one is least stabilized.

    The standard order for substituted benzenediazonium salts is:

    • Stronger electron-withdrawing substituents stabilize most.
    • Para/ortho withdrawing effects via resonance are more effective than only weak effects.
    • Electron-donating substituents destabilize the diazonium ion most.
  3. Relative stability trend

    Based on these effects, the stability order comes out as: A>C>D>BA > C > D > BA>C>D>B

  4. Check with options

    • Option A: A>B>C>DA > B > C > DA>B>C>D ❌
    • Option B: A>C>D>BA > C > D > BA>C>D>B ✅
    • Option C: C>A>D>BC > A > D > BC>A>D>B ❌
    • Option D: C>D>B>AC > D > B > AC>D>B>A ❌
  5. Final answer

    Therefore, the correct option is: B\boxed{B}B​

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