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Compounds Containing Nitrogen question

2016 · Shift 0 · Q13
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Compounds Containing Nitrogen question

2016 · Shift 0 · Q13

JEE MainChemistryCompounds Containing NitrogenMCQ+4 / −1
In the Hofmann bromamide degradation reaction, the number of moles of NaOHNaOHNaOH and Br2Br_2Br2​ used per mole of amine produced are:
  1. A
    Four moles of NaOHNaOHNaOH and two moles of Br2Br_2Br2​.
  2. B
    Two moles of NaOHNaOHNaOH and two moles of Br2Br_2Br2​
  3. C
    Four moles of NaOHNaOHNaOH and one mole of Br2Br_2Br2​
  4. D
    One mole of NaOHNaOHNaOH and one mole of Br2Br_2Br2​
View written solutionFree

Correct answer: C

  1. Hofmann bromamide degradation reaction converts an amide into a primary amine with one carbon less.

    The general reaction is: RCONH2+Br2+4NaOH→RNH2+2NaBr+Na2CO3+2H2ORCONH_2 + Br_2 + 4NaOH \rightarrow RNH_2 + 2NaBr + Na_2CO_3 + 2H_2ORCONH2​+Br2​+4NaOH→RNH2​+2NaBr+Na2​CO3​+2H2​O

  2. From the balanced equation, for 1 mole of amine produced (RNH2)\left(RNH_2\right)(RNH2​), the reagents required are:

    • 111 mole of Br2Br_2Br2​
    • 444 moles of NaOHNaOHNaOH

  3. Therefore, the correct option is: C: Four moles of NaOH and one mole of Br2\boxed{\text{C: Four moles of } NaOH \text{ and one mole of } Br_2}C: Four moles of NaOH and one mole of Br2​​

  4. Comparison with stored answer:

    Stored correct answer = C

    Our derived answer = C

    So, they agree.

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