Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Chemical Kinetics and Nuclear Chemistry question

2022 · 27 Jun · Shift 1 · Q15
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /Chemical Kinetics and Nuclear Chemistry
  5. /2022 · 27 Jun · Shift 1 · Q15

Chemical Kinetics and Nuclear Chemistry question

2022 · 27 Jun · Shift 1 · Q15

JEE MainChemistryChemical Kinetics and Nuclear ChemistryNumerical+4 / −1
The rate constant for a first order reaction is given by the following equation: ln⁡k=33.24−2.0×104 KT\ln k = 33.24 - {{2.0 \times {{10}^4}\,K} \over T}lnk=33.24−T2.0×104K​ The activation energy for the reaction is given by ‾\underline{\hspace{2cm}}​ kJ mol −-− 1. (In nearest integer) (Given : R = 8.3 J K −-− 1 mol −-− 1)
Numerical answer
View written solutionFree

Correct answer: 166

  1. Use the Arrhenius equation in logarithmic form:
ln⁡k=ln⁡A−EaRT\ln k = \ln A - \frac{E_a}{RT}lnk=lnA−RTEa​​
  1. Compare this with the given equation:
ln⁡k=33.24−2.0×104 KT\ln k = 33.24 - \frac{2.0\times 10^4\,K}{T}lnk=33.24−T2.0×104K​

So,

EaR=2.0×104\frac{E_a}{R} = 2.0\times 10^4REa​​=2.0×104
  1. Therefore,
Ea=R×2.0×104E_a = R \times 2.0\times 10^4Ea​=R×2.0×104

Given:

R=8.3  J K−1mol−1R = 8.3\; \text{J K}^{-1}\text{mol}^{-1}R=8.3J K−1mol−1

Hence,

Ea=8.3×2.0×104E_a = 8.3 \times 2.0\times 10^4Ea​=8.3×2.0×104 Ea=1.66×105  J mol−1E_a = 1.66\times 10^5\; \text{J mol}^{-1}Ea​=1.66×105J mol−1
  1. Convert to kJ mol−1^{-1}−1:
Ea=1.66×1051000=166  kJ mol−1E_a = \frac{1.66\times 10^5}{1000} = 166\; \text{kJ mol}^{-1}Ea​=10001.66×105​=166kJ mol−1
  1. Nearest integer:
166\boxed{166}166​
PreviousNext

More from Chemical Kinetics and Nuclear Chemistry

  • It has been found that for a chemical reaction with rise in temperature by 9 K the rate constant gets doubled. Assuming a reaction to be occurring at 300 K, the value of activation energy is found to be ​ kJ mol…2022 · Numerical
  • For kinetic study of the reaction of iodide ion with H2​O2​ at room temperature : (A) Always use freshly prepared starch solution. (B) Always keep the concentration of sodium thiosulphate solution less than that of…2022 · MCQ
  • For the given first order reaction A→B the half life of the reaction is 0.3010 min. The ratio of the initial concentration of reactant to the concentration of reactant at time 2.0 min…2022 · Numerical
  • For a reaction, given below is the graph of lnk vs T1​. The activation energy for the reaction is equal to ​calmol−1. (nearest integer) (Given : R=2calK−1 mol−1… Includes diagram2022 · Numerical
  • For a first order reaction A → B, the rate constant, k = 5.5 × 10 − 14 s − 1. The time required for 67% completion of reaction is x × 10 − 1 times the half life of reaction. The value of x is ​…2022 · Numerical
  • A radioactive element has a half life of 200 days. The percentage of original activity remaining after 83 days is ​. (Nearest integer) (Given : antilog 0.125 = 1.333, antilog 0.693 = 4.93)2022 · Numerical
  • The reaction between X and Y is first order with respect to X and zero order with respect to Y. Examine the data of table and calculate ratio of numerical values of M and L. (Nearest Integer) Includes table2022 · Numerical
  • Assuming 1μg of trace radioactive element X with a half life of 30 years is absorbed by a growing tree. The amount of X remaining in the tree after 100 years is ​×10−1μg.…2022 · Numerical