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Chemical Kinetics and Nuclear Chemistry question

2005 · Shift 0 · Q38
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Chemical Kinetics and Nuclear Chemistry question

2005 · Shift 0 · Q38

JEE MainChemistryChemical Kinetics and Nuclear ChemistryMCQ+4 / −1
A reaction involving two different reactants can never be
  1. A
    Unimolecular reaction
  2. B
    First order reaction
  3. C
    second order reaction
  4. D
    Bimolecular reaction
View written solutionFree

Correct answer: A

  1. Interpret the statement

The reaction involves two different reactants, so a typical form is:

A+B→productsA + B \to \text{products}A+B→products

We must find what such a reaction can never be.


  1. Check each option

Option A: Unimolecular reaction

A unimolecular reaction is an elementary reaction in which only one molecule participates in the rate-determining event, e.g.

A→productsA \to \text{products}A→products

Since the question says the reaction involves two different reactants, it cannot be unimolecular.

So, A is impossible.


Option B: First order reaction

A reaction involving two reactants can still be first order overall in some cases.

Example:

A+B→productsA + B \to \text{products}A+B→products

with rate law

Rate=k[A]1[B]0=k[A]\text{Rate} = k[A]^1[B]^0 = k[A]Rate=k[A]1[B]0=k[A]

or under pseudo-first-order conditions when one reactant is in large excess.

So, such a reaction can be first order.


Option C: Second order reaction

If the rate law is

Rate=k[A][B]\text{Rate} = k[A][B]Rate=k[A][B]

then overall order is

1+1=21+1=21+1=2

So, a reaction involving two reactants can be second order.


Option D: Bimolecular reaction

A bimolecular reaction is an elementary process involving collision of two molecules, such as:

A+B→productsA + B \to \text{products}A+B→products

This exactly matches a reaction involving two different reactants.

So, it can be bimolecular.


  1. Conclusion

A reaction involving two different reactants can never be a unimolecular reaction.

A\boxed{\text{A}}A​

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