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Biomolecules question

2019 · 11 Jan · Shift 2 · Q8
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Biomolecules question

2019 · 11 Jan · Shift 2 · Q8

JEE MainChemistryBiomoleculesMCQ+4 / −1
The correct match between Item I and Item II is :

Item I Item II
(A) Ester test (P) Tyr
(B) Carbylamine test (Q) Asp
(C) Phthalein dye test
(R) Ser
(S) Lys
  1. A
    (A) →\to→(Q); (B) →\to→(S); (C) →\to→(P)
  2. B
    (A) →\to→(R); (B) →\to→(S); (C) →\to→(Q)
  3. C
    (A) →\to→(R); (B) →\to→(Q); (C) →\to→(P)
  4. D
    (A) →\to→(Q); (B) →\to→(S); (C) →\to→(R)
View written solutionFree

Correct answer: A

  1. Identify what each test detects

    We match the given qualitative tests with amino acids based on their functional groups.

    • Ester test: This is given by compounds containing a carboxylic acid group (−COOH)(-COOH)(−COOH), since carboxylic acids form esters with alcohols.
    • Carbylamine test: This is given by primary amines (−NH2)(-NH_2)(−NH2​).
    • Phthalein dye test: This is characteristic of phenolic group (−OH(-OH(−OH attached to aromatic ring))).
  2. Examine the amino acids given

    • Tyr = Tyrosine: contains a phenolic −OH-OH−OH group.
    • Asp = Aspartic acid: contains an extra carboxylic acid group in the side chain.
    • Ser = Serine: contains an alcohol −CH2OH-CH_2OH−CH2​OH side chain, but not phenolic.
    • Lys = Lysine: contains an extra primary amino group in the side chain.
  3. Match each test

    (A) Ester test

    • Best matched by Aspartic acid (Asp) due to extra −COOH-COOH−COOH group.
    • So, (A)→(Q)(A) \to (Q)(A)→(Q).

    (B) Carbylamine test

    • Requires a primary amine.
    • Lysine (Lys) has an additional primary amino group.
    • So, (B)→(S)(B) \to (S)(B)→(S).

    (C) Phthalein dye test

    • Given by phenols.
    • Tyrosine (Tyr) contains phenolic −OH-OH−OH.
    • So, (C)→(P)(C) \to (P)(C)→(P).
  4. Final matching

    (A)→(Q),(B)→(S),(C)→(P)(A) \to (Q), \quad (B) \to (S), \quad (C) \to (P)(A)→(Q),(B)→(S),(C)→(P)
  5. Compare with options

    This corresponds to Option A.

  6. Comparison with stored answer

    Stored correct answer = A.

    Our derived answer also = A.

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