Identify the relation between the two molecules

$\alpha$-D-(+)-glucose and $\beta$-D-(+)-glucose are cyclic forms of D-glucose.

Recall the definition of anomers

When a monosaccharide cyclizes, the carbonyl carbon becomes a new chiral center called the anomeric carbon.

• In glucose, this is carbon $C_1$.
• If two cyclic forms differ only in configuration at the anomeric carbon, they are called anomers.

Apply to $\alpha$- and $\beta$-D-glucose

• $\alpha$-D-glucose: configuration at anomeric carbon has the $\mathrm{OH}$ group oriented differently.
• $\beta$-D-glucose: differs from the $\alpha$ form only at $C_1$.

Therefore, these two are anomers.

Check other options

• A: conformers: Conformers differ by rotation about single bonds, not by configuration at the anomeric carbon. Incorrect.
• B: epimers: Epimers differ at one chiral center, but in carbohydrate chemistry, the special term for difference at the anomeric carbon is anomers. Though anomers are a special type of epimers, the best answer here is anomers. Incorrect as the intended answer.
• D: enantiomers: Enantiomers are non-superimposable mirror images. Both are D-glucose forms, so not enantiomers. Incorrect.

Final answer

The correct option is C: anomers.