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Basics of Organic Chemistry question

2024 · 8 Apr · Shift 1 · Q28
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Basics of Organic Chemistry question

2024 · 8 Apr · Shift 1 · Q28

JEE MainChemistryBasics of Organic ChemistryNumerical+4 / −1
The number of optical isomers in following compound is : ‾\underline{\hspace{2cm}}​. JEE Main 2024 (Online) 8th April Morning Shift Chemistry - Basics of Organic Chemistry Question 44 English
Numerical answer
View written solutionFree

Correct answer: 32

The question asks for the number of optical isomers, but the structure of the compound is missing from the prompt.

To determine the number of optical isomers, we must know:

  1. The exact carbon skeleton / ring system
  2. The number of stereogenic centers
  3. Whether any internal plane of symmetry is present
  4. Whether meso forms exist
  5. Whether other stereogenic elements (axial, geometrical, etc.) are involved

Without the actual compound, the answer cannot be derived uniquely.

What would normally be done

If a compound has nnn stereogenic centers and no symmetry, the maximum number of optical isomers is: 2n2^n2n If meso forms or symmetry are present, the number is reduced.

Since the stored correct answer is 32, that suggests a likely situation such as: 25=322^5 = 3225=32 which would correspond to a compound with 5 independent chiral centers and no meso form.

However, this is only an inference — not a valid derivation without the structure.

Conclusion

Because the compound figure is absent, the problem is incomplete. So I cannot rigorously verify that the answer is 32 from first principles.

If you upload or paste the structure, I can compute the exact number step-by-step.

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