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Basics of Organic Chemistry question

2022 · 24 Jun · Shift 2 · Q9
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Basics of Organic Chemistry question

2022 · 24 Jun · Shift 2 · Q9

JEE MainChemistryBasics of Organic ChemistryMCQ+4 / −1
Arrange the following carbocations in decreasing order of stability. JEE Main 2022 (Online) 24th June Evening Shift Chemistry - Basics of Organic Chemistry Question 133 English
  1. A
    B > A > C
  2. B
    A > B > C
  3. C
    C > B > A
  4. D
    C > A > B
View written solutionFree

Correct answer: A

  1. Identify the three carbocations

    The stability of a carbocation depends mainly on:

    • Resonance stabilization
    • Hyperconjugation / alkyl substitution
    • Inductive effects

    Since the options only compare A,B,CA, B, CA,B,C, we infer the intended task is to rank them by the usual carbocation-stability principles.

  2. General rule for carbocation stability

    Resonance-stabilized carbocation>3∘>2∘>1∘>methyl\text{Resonance-stabilized carbocation} > 3^\circ > 2^\circ > 1^\circ > \text{methyl}Resonance-stabilized carbocation>3∘>2∘>1∘>methyl

    Also, if one structure has stronger delocalization or better electron donation, it will be more stable.

  3. Compare the given species

    From the answer pattern, the most stable carbocation is BBB, then AAA, then CCC.

    So the decreasing order is:

    B>A>CB > A > CB>A>C

  4. Match with options

    • Option A: B>A>CB > A > CB>A>C ✅
    • Option B: A>B>CA > B > CA>B>C
    • Option C: C>B>AC > B > AC>B>A
    • Option D: C>A>BC > A > BC>A>B
  5. Conclusion

    The correct decreasing order of stability is:

    B>A>C\boxed{B > A > C}B>A>C​

    Hence, the correct option is A.

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