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Basics of Organic Chemistry question

2018 · 15 Apr · Shift 1 · Q7
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Basics of Organic Chemistry question

2018 · 15 Apr · Shift 1 · Q7

JEE MainChemistryBasics of Organic ChemistryMCQ+4 / −1
The correct match between items of List-I and List-II is :

List - I List - II
(A) Coloured impurity (P) Steam distilation
(B) Mixture of o-nitrophenol
and p-nitrophenol		 (Q) Fractional distilation
(C) Crude Naphtha (R) Charcoal treatment
(d) Mixture of glycerol
and sugars		 (S) Distillation under
reduced pressure
  1. A
    (A)-(R), (B)-(S), (C)-(P), (D)-(Q)
  2. B
    (A)-(R), (B)-(P), (C)-(S), (D)-(Q)
  3. C
    (A)-(R), (B)-(P), (C)-(Q), (D)-(S)
  4. D
    (A)-(P), (B)-(S), (C)-(R), (D)-(Q)
View written solutionFree

Correct answer: C

  1. Identify the purification/separation methods in List-II
  • (P)(P)(P) Steam distillation
  • (Q)(Q)(Q) Fractional distillation
  • (R)(R)(R) Charcoal treatment
  • (S)(S)(S) Distillation under reduced pressure
  1. Match each item of List-I

(A) Coloured impurity

Coloured impurities are commonly removed by adsorption over animal/activated charcoal.

So, A→RA \to RA→R

(B) Mixture of ooo-nitrophenol and ppp-nitrophenol

ooo-Nitrophenol shows intramolecular hydrogen bonding, so it is more volatile.
ppp-Nitrophenol shows intermolecular hydrogen bonding, so it is less volatile.

Hence they can be separated by steam distillation.

So, B→PB \to PB→P

(C) Crude Naphtha

Crude naphtha is a mixture of hydrocarbons with different but relatively close boiling points, so it is separated by fractional distillation.

So, C→QC \to QC→Q

(D) Mixture of glycerol and sugars

Glycerol has a very high boiling point and may decompose on strong heating. Such substances are purified by distillation under reduced pressure.

So, D→SD \to SD→S

  1. Final matching
(A)−(R),(B)−(P),(C)−(Q),(D)−(S)(A)-(R),\quad (B)-(P),\quad (C)-(Q),\quad (D)-(S)(A)−(R),(B)−(P),(C)−(Q),(D)−(S)

This corresponds to Option C.

  1. Comparison with stored answer

Stored correct answer = C
Derived answer = C
So, they agree.

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