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Aldehydes Ketones and Carboxylic Acids question

2025 · 8 Apr · Shift 2 · Q16
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Aldehydes Ketones and Carboxylic Acids question

2025 · 8 Apr · Shift 2 · Q16

JEE MainChemistryAldehydes Ketones and Carboxylic AcidsMCQ+4 / −1
When JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 10 English undergoes intramolecular aldol condensation, the major product formed is :
  1. A
    JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 10 English Option 1
  2. B
    JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 10 English Option 2
  3. C
    JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 10 English Option 3
  4. D
    JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 10 English Option 4
View written solutionFree

Correct answer: B

The question statement appears to be incomplete: the substrate structure and all four option structures are missing.

To determine the product of an intramolecular aldol condensation, I need:

  1. The given carbonyl compound/substrate
  2. The structures of options A, B, C, and D

Without the reactant structure, the product cannot be derived uniquely, because intramolecular aldol condensation depends on:

  • the number of carbon atoms between carbonyl groups,
  • whether the compound is a dialdehyde/diketone/keto-aldehyde,
  • which α\alphaα-hydrogen is abstracted,
  • whether a 5-membered or 6-membered ring is formed,
  • and the dehydration pattern of the aldol product.

What is normally done

For an intramolecular aldol condensation:

  1. Identify the enolate-forming α\alphaα-carbon.
  2. Check possible cyclizations.
  3. Prefer formation of 5-membered or 6-membered rings.
  4. Form the β\betaβ-hydroxy carbonyl intermediate.
  5. Dehydrate to give the α,β\alpha,\betaα,β-unsaturated carbonyl compound.

But here

Since the actual compound and options are absent, I cannot genuinely verify whether option B is correct.

Please resend the question with the reactant and option structures visible, and I will solve it step-by-step properly.

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