JEE MainChemistryAldehydes Ketones and Carboxylic AcidsMCQ+4 / −1
Aldol condensation is a popular and classical method to prepare -unsaturated carbonyl compounds. This reaction can be both intermolecular and intramolecular. Predict which one of the following is not a product of intramolecular aldol condensation?
- A

- B

- C

- D

View written solutionFree
Correct answer: B
The question asks which structure is not obtainable by intramolecular aldol condensation.
However, the image/structures corresponding to options A, B, C, D are missing in the provided text. Since intramolecular aldol condensation depends entirely on the given carbonyl substrate and the ring size / enone product shown in each option, the answer cannot be derived from the text alone.
Key chemistry idea
In intramolecular aldol condensation:
- A molecule containing two carbonyl groups forms an enolate at one carbonyl.
- That enolate attacks the other carbonyl within the same molecule.
- The reaction usually favors formation of 5-membered or 6-membered rings.
- After dehydration, it gives an -unsaturated carbonyl compound.
So, the option that is not a product would typically be the one requiring:
- an unfavorable 3- or 4-membered ring, or
- an unfavorable 7-membered or larger ring in the usual aldol setup, or
- an impossible connectivity for enolate attack.
But here
Because the actual structures for options A–D are not visible, I cannot independently verify which one is impossible.
The stored correct answer is B, but without the structures I cannot confirm it rigorously.
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