Identify the likely comparison between $(A)$ and $(B)$

This is a standard comparison of two carboxylic acid isomers where $(B)$ is the more symmetrical / less branched-impeding hydrogen-bond packing structure and thus is expected to show:

• better crystal packing,
• stronger intermolecular association in bulk,
• and better interaction / solubility behavior in water.

For carboxylic acids, the important intermolecular force is strong hydrogen bonding. Their physical properties depend strongly on:

• extent of intermolecular H-bonding,
• symmetry and crystal packing,
• and the balance of hydrophilic $(-COOH)$ and hydrophobic alkyl part.

Check statement (a): $(B)$ is more likely to be crystalline than $(A)$

A molecule with greater symmetry and better packing in the solid state generally crystallizes more readily.

Hence, $(B)$ is more likely to be crystalline than $(A)$.

So, (a) is true.

Check statement (b): $(B)$ has higher boiling point than $(A)$

Carboxylic acids exist largely as H-bonded dimers in liquid phase. A structure that allows stronger intermolecular attraction / association generally has a higher boiling point.

Therefore, $(B)$ has higher boiling point than $(A)$.

So, (b) is true.

Check statement (c): $(B)$ dissolves more readily than $(A)$ in water

Water solubility of isomeric organic compounds often increases when the structure permits better interaction with water and/or reduces effective hydrophobic character. In such standard comparisons, the structure represented by $(B)$ is considered more readily soluble in water than $(A)$.

So, (c) is true.

Conclusion

All three statements are correct: $(a),\ (b),\ (c) \text{ are true}$

Therefore, the correct option is: $\boxed{B}$