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Rotational Motion question

2009 · Shift 2 · Q46
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Rotational Motion question

2009 · Shift 2 · Q46

JEE AdvancedPhysicsRotational MotionMultiple correct+4 / −2
A sphere is rolling without slipping on a fixed horizontal plane surface. In the figure below, A is the point of contact, B is the centre of the sphere and C is its topmost point. Then, IIT-JEE 2009 Paper 2 Offline Physics - Rotational Motion Question 20 English
  1. A
    V→C−V→A=2(V→B−V→C){\overrightarrow V _C} - {\overrightarrow V _A} = 2({\overrightarrow V _B} - {\overrightarrow V _C})VC​−VA​=2(VB​−VC​)
  2. B
    V→C−V→B=V→B−V→A{\overrightarrow V _C} - {\overrightarrow V _B} = {\overrightarrow V _B} - {\overrightarrow V _A}VC​−VB​=VB​−VA​
  3. C
    ∣V→C−V→A∣=2∣V→B−V→C∣|{\overrightarrow V _C} - {\overrightarrow V _A}| = 2|{\overrightarrow V _B} - {\overrightarrow V _C}|∣VC​−VA​∣=2∣VB​−VC​∣
  4. D
    ∣V→C−V→A∣=4∣V→B∣|{\overrightarrow V _C} - {\overrightarrow V _A}| = 4|{\overrightarrow V _B}|∣VC​−VA​∣=4∣VB​∣
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