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Rotational Motion question

2008 · Shift 2 · Q61
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Rotational Motion question

2008 · Shift 2 · Q61

JEE AdvancedPhysicsRotational MotionMCQ+3 / −1
A uniform thin cylindrical disk of mass M and radius R is attached to two identical massless springs of spring constant kkk which are fixed to the wall as shown in the figure. The springs are attached to the axle of the disk symmetrically on either side at a distance d from its centre. The axle is massless and both the springs and the axle are in a horizontal plane. The unstretched length of each spring is L. The disk is initially at its equilibrium position with its centre of mass (CM) at a distance L from the wall. The disk rolls without slipping with velocity V→0=V0i^{\overrightarrow V _0} = {V_0}\widehat iV0​=V0​i. the coefficient of friction is μ\muμ. IIT-JEE 2008 Paper 2 Offline Physics - Rotational Motion Question 15 English ComprehensionThe net external force acting on the disk when its centre of mass is at displacement x with respect to its equilibrium position is :
  1. A
    −kx- kx−kx
  2. B
    −2kx- 2kx−2kx
  3. C
    −2kx3- {{2kx} \over 3}−32kx​
  4. D
    −4kx3- {{4kx} \over 3}−34kx​
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