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Properties of Matter question

2024 · Shift 2 · Q40
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Properties of Matter question

2024 · Shift 2 · Q40

JEE AdvancedPhysicsProperties of MatterMultiple correct+4 / −2
A table tennis ball has radius (3/2)×10−2 m(3 / 2) \times 10^{-2} \mathrm{~m}(3/2)×10−2 m and mass (22/7)×10−3 kg(22 / 7) \times 10^{-3} \mathrm{~kg}(22/7)×10−3 kg. It is slowly pushed down into a swimming pool to a depth of d=0.7 md=0.7 \mathrm{~m}d=0.7 m below the water surface and then released from rest. It emerges from the water surface at speed vvv, without getting wet, and rises up to a height HHH. Which of the following option(s) is(are) correct? [Given: π=22/7,g=10 m s−2\pi=22 / 7, g=10 \mathrm{~m} \mathrm{~s}^{-2}π=22/7,g=10 m s−2, density of water =1×103 kg m−3=1 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}=1×103 kg m−3, viscosity of water =1×10−3 Pa=1 \times 10^{-3} \mathrm{~Pa}=1×10−3 Pa-s.]
  1. A
    The work done in pushing the ball to the depth ddd is 0.077 J0.077 \mathrm{~J}0.077 J.
  2. B
    If we neglect the viscous force in water, then the speed v=7 m/sv=7 \mathrm{~m} / \mathrm{s}v=7 m/s.
  3. C
    If we neglect the viscous force in water, then the height H=1.4 mH=1.4 \mathrm{~m}H=1.4 m.
  4. D
    The ratio of the magnitudes of the net force excluding the viscous force to the maximum viscous force in water is 500/9500 / 9500/9.
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