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Heat and Thermodynamics question

2007 · Shift 1 · Q61
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  5. /2007 · Shift 1 · Q61

Heat and Thermodynamics question

2007 · Shift 1 · Q61

JEE AdvancedPhysicsHeat and ThermodynamicsMCQ+3 / −1
A fixed thermally conducting cylinder has a radius RRR and height L0L_0L0​. The cylinder is open at its bottom and has a small hole at its top. A piston of mass MMM is held at a distance LLL from the top surface, as shown in the figure. The atmospheric pressure is P0P_0P0​. IIT-JEE 2007 Paper 1 Offline Physics - Heat and Thermodynamics Question 18 English ComprehensionThe piston is taken completely out of the cylinder. The hole at the top is sealed. A water tank is brought below the cylinder and put in a position so that the water surface in the tank is at the same level as the top of the cylinder as shown in the figure. The density of the water is ρ\rhoρ. In equilibrium, the height H of the water column in the cylinder satisfies IIT-JEE 2007 Paper 1 Offline Physics - Heat and Thermodynamics Question 18 English
  1. A
    ρg(L0−H)2+P0(L0−H)+L0P0=0\rho g{({L_0} - H)^2} + {P_0}({L_0} - H) + {L_0}{P_0} = 0ρg(L0​−H)2+P0​(L0​−H)+L0​P0​=0
  2. B
    ρg(L0−H)2−P0(L0−H)−L0P0=0\rho g{({L_0} - H)^2} - {P_0}({L_0} - H) - {L_0}{P_0} = 0ρg(L0​−H)2−P0​(L0​−H)−L0​P0​=0
  3. C
    ρg(L0−H)2+P0(L0−H)−L0P0=0\rho g{({L_0} - H)^2} + {P_0}({L_0} - H) - {L_0}{P_0} = 0ρg(L0​−H)2+P0​(L0​−H)−L0​P0​=0
  4. D
    ρg(L0−H)2−P0(L0−H)+L0P0=0\rho g{({L_0} - H)^2} - {P_0}({L_0} - H) + {L_0}{P_0} = 0ρg(L0​−H)2−P0​(L0​−H)+L0​P0​=0
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