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Electromagnetic Induction question

2025 · Shift 1 · Q37
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  5. /2025 · Shift 1 · Q37

Electromagnetic Induction question

2025 · Shift 1 · Q37

JEE AdvancedPhysicsElectromagnetic InductionMultiple correct+4 / −2
A conducting square loop of side LLL, mass MMM and resistance RRR is moving in the XYX YXY plane with its edges parallel to the XXX and YYY axes. The region y≥0y \geq 0y≥0 has a uniform magnetic field, B⃗=B0k^\vec{B}=B_0 \widehat{k}B=B0​k. The magnetic field is zero everywhere else. At time t=0t=0t=0, the loop starts to enter the magnetic field with an initial velocity v0ȷ^ m/sv_0 \hat{\jmath} \mathrm{~m} / \mathrm{s}v0​^​ m/s, as shown in the figure. Considering the quantity K=B02L2RMK=\frac{B_0^2 L^2}{R M}K=RMB02​L2​ in appropriate units, ignoring self-inductance of the loop and gravity, which of the following statements is/are correct: JEE Advanced 2025 Paper 1 Online Physics - Electromagnetic Induction Question 1 English
  1. A
    If v0=1.5KLv_0 = 1.5KLv0​=1.5KL, the loop will stop before it enters completely inside the region of magnetic field.
  2. B
    When the complete loop is inside the region of magnetic field, the net force acting on the loop is zero.
  3. C
    If v0=KL10v_0 = \frac{KL}{10}v0​=10KL​, the loop comes to rest at t=(1K)ln⁡(52)t = \left(\frac{1}{K}\right) \ln\left(\frac{5}{2}\right)t=(K1​)ln(25​).
  4. D
    If v0=3KLv_0 = 3KLv0​=3KL, the complete loop enters inside the region of magnetic field at time t=(1K)ln⁡(32)t = \left(\frac{1}{K}\right) \ln\left(\frac{3}{2}\right)t=(K1​)ln(23​).
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