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Electromagnetic Induction question

2012 · Shift 1 · Q56
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Electromagnetic Induction question

2012 · Shift 1 · Q56

JEE AdvancedPhysicsElectromagnetic InductionNumerical+4 / −1
A circular wire loop of radius R is placed in the xy plane centred at the origin O. A square loop of side a(a << R) having two turns is placed with its centre at z = 3\sqrt33​ R along the axis of the circular wire loop, as shown in the figure. The plane of the square loop makes an angle of 45 ∘^\circ∘ with respect to z-axis. If the mutual inductance between the loops is given by μ0a22p/2R{{{\mu _0}{a^2}} \over {{2^{p/2}}R}}2p/2Rμ0​a2​, then the value of p is ‾\underline{\hspace{2cm}}​. IIT-JEE 2012 Paper 1 Offline Physics - Electromagnetic Induction Question 8 English
Numerical answer
View written solutionFree

Correct answer: 7

The question text is incomplete. It currently reads:

"A circular wire loop of radius RRR is placed in the xyxyxy plane centred at the origin OOO. A square loop of side a(aa(aa(a ..."

The essential part of the statement is missing after this, so the physical setup is undefined. In particular, to solve an electromagnetic induction problem, we would need information such as:

  1. the full geometry of the square loop,
  2. its position/orientation relative to the circular loop,
  3. whether current in one loop is changing or one loop is moving/rotating,
  4. what quantity is to be calculated.

Without these details, the problem cannot be solved uniquely.

Since the statement is truncated, I cannot derive the integer answer from first principles. Therefore I cannot verify that the stored answer 777 is correct based on the provided text alone.

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