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Dual Nature of Radiation question

2022 · Shift 2 · Q52
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Dual Nature of Radiation question

2022 · Shift 2 · Q52

JEE AdvancedPhysicsDual Nature of RadiationMCQ+3 / −1
When light of a given wavelength is incident on a metallic surface, the minimum potential needed to stop the emitted photoelectrons is 6.0 V6.0 \mathrm{~V}6.0 V. This potential drops to 0.6 V0.6 \mathrm{~V}0.6 V if another source with wavelength four times that of the first one and intensity half of the first one is used. What are the wavelength of the first source and the work function of the metal, respectively? [Take hce=1.24×10−6JmC−1\frac{h c}{e}=1.24 \times10^{-6} \mathrm{JmC}^{-1}ehc​=1.24×10−6JmC−1.]
  1. A
    1.72×10−7 m,1.20eV1.72 \times 10^{-7} \mathrm{~m}, 1.20 \mathrm{eV}1.72×10−7 m,1.20eV
  2. B
    1.72×10−7 m,5.60eV1.72 \times 10^{-7} \mathrm{~m}, 5.60 \mathrm{eV}1.72×10−7 m,5.60eV
  3. C
    3.78×10−7 m,5.60eV3.78 \times 10^{-7} \mathrm{~m}, 5.60 \mathrm{eV}3.78×10−7 m,5.60eV
  4. D
    3.78×10−7 m,1.20eV3.78 \times 10^{-7} \mathrm{~m}, 1.20 \mathrm{eV}3.78×10−7 m,1.20eV
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