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Dual Nature of Radiation question

2013 · Shift 2 · Q47
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Dual Nature of Radiation question

2013 · Shift 2 · Q47

JEE AdvancedPhysicsDual Nature of RadiationMultiple correct+3 / −0.75
Using the expression 2dsin⁡θ=λ2d\sin \theta = \lambda2dsinθ=λ, one calculates the values of d by measuring the corresponding angles θ\thetaθ in the range 0 to 90o. The wavelength λ\lambdaλ is exactly known and the error in θ\thetaθ is constant for all values of θ\thetaθ. As θ\thetaθ increases from 0o
  1. A
    the absolute error in d remains constant
  2. B
    the absolute error in d increases
  3. C
    the fractional error in d remains constant
  4. D
    the fractional error in d decreases
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