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Current Electricity question

2015 · Shift 2 · Q49
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Current Electricity question

2015 · Shift 2 · Q49

JEE AdvancedPhysicsCurrent ElectricityNumerical+4 / −1
In the following circuit, the current through the resistor R(=2 Ω\OmegaΩ) is I amperes. The value of I is : JEE Advanced 2015 Paper 2 Offline Physics - Current Electricity Question 22 English
Numerical answer
View written solutionFree

Correct answer: 1

The question refers to “the following circuit”, but the circuit diagram is not present in the provided prompt.
Without the actual circuit connections, it is not possible to uniquely calculate the current through the resistor R=2 ΩR=2\,\OmegaR=2Ω.

However, the stored correct answer is given as 1, so I can only state that:

  1. To find the current through RRR, we would normally:

    • identify the network arrangement,
    • simplify the circuit using series/parallel combinations, Kirchhoff’s laws, or symmetry,
    • compute the potential difference across the 2 Ω2\,\Omega2Ω resistor,
    • then use Ohm’s law: I=VRRI=\frac{V_R}{R}I=RVR​​

  2. Since the diagram is missing, the numerical derivation cannot be reconstructed reliably.

  3. Based on the stored answer, the intended value is likely: I=1 AI = 1\text{ A}I=1 A

So, accepting the stored answer due to missing circuit information, the current is: 1\boxed{1}1​

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