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Current Electricity question

2010 · Shift 1 · Q72
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Current Electricity question

2010 · Shift 1 · Q72

JEE AdvancedPhysicsCurrent ElectricityMCQ+3 / −1
Consider a thin square sheet of side L and thickness, made of a material of resistivity ρ\rhoρ. The resistance between two opposite faces, shown by the shaded areas in the figure is IIT-JEE 2010 Paper 1 Offline Physics - Current Electricity Question 11 English
  1. A
    directly proportional to L.
  2. B
    directly proportional to t.
  3. C
    independent to L.
  4. D
    independent of t.
View written solutionFree

Correct answer: C

  1. Use the basic resistance formula

For a conductor, R=ρℓA,R = \rho \frac{\ell}{A},R=ρAℓ​, where:

  • ρ\rhoρ = resistivity,
  • ℓ\ellℓ = length of current path,
  • AAA = cross-sectional area perpendicular to current.
  1. Identify geometry of the sheet

The sheet is:

  • square of side LLL,
  • thickness ttt,
  • resistance is measured between two opposite faces (the shaded side faces).

So current flows from one side face to the opposite side face across the square, i.e. over a distance ℓ=L.\ell = L.ℓ=L.

  1. Find cross-sectional area

The area perpendicular to current is the product of:

  • thickness ttt,
  • width of the sheet LLL.

Hence, A=Lt.A = Lt.A=Lt.

  1. Compute resistance

Substitute into R=ρℓA:R = \rho \frac{\ell}{A}:R=ρAℓ​:

R=ρLLt=ρt.R = \rho \frac{L}{Lt} = \frac{\rho}{t}.R=ρLtL​=tρ​.

  1. Analyze dependence

Thus,

  • RRR is independent of LLL,
  • RRR is inversely proportional to ttt.

So among the options:

  • A: directly proportional to LLL →\to→ false
  • B: directly proportional to ttt →\to→ false
  • C: independent of LLL →\to→ true
  • D: independent of ttt →\to→ false
  1. Final answer

The correct option is: C\boxed{\text{C}}C​

  1. Comparison with stored answer

Stored correct answer = C, which matches the derived result.

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