Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Atoms and Nuclei question

2013 · Shift 2 · Q60
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Advanced
  3. /Physics
  4. /Atoms and Nuclei
  5. /2013 · Shift 2 · Q60

Atoms and Nuclei question

2013 · Shift 2 · Q60

JEE AdvancedPhysicsAtoms and NucleiMCQ+3 / −1

Match List I of the nuclear processes with List II containing parent nucleus and one of the end products of each process and then select the correct answer using the codes given below the lists :

List I List II
P. Alpha decay 1. 815O→715N+..._8^{15}O \to _7^{15}N + ...815​O→715​N+...
Q. β+{\beta ^ + }β+ decay 2. 91238U→90234Th+..._{91}^{238}U \to _{90}^{234}Th + ...91238​U→90234​Th+...
R. Fission 3. 83185Bi→82184Pb+..._{83}^{185}Bi \to _{82}^{184}Pb + ...83185​Bi→82184​Pb+...
S. Proton emission 4. 94239Pu→57140La+..._{94}^{239}Pu \to _{57}^{140}La + ...94239​Pu→57140​La+...

  1. A
    P-4, Q-2, R-1, S-3
  2. B
    P-1, Q-3, R-2, S-4
  3. C
    P-2, Q-1, R-4, S-3
  4. D
    P-4, Q-3, R-2, S-1
View written solutionFree

Correct answer: C

  1. Identify each process from List II by checking the change in mass number AAA and atomic number ZZZ.

  1. Process 1: 815O→715N+…{}_8^{15}O \to {}_7^{15}N + \dots815​O→715​N+…

    • Mass number unchanged: 15→1515 \to 1515→15
    • Atomic number decreases by 1: 8→78 \to 78→7

    This is β+\beta^+β+ decay because in positron emission, p→n+e++νp \to n + e^+ + \nup→n+e++ν so ZZZ decreases by 1 while AAA remains same.

    Hence, Q→1Q \to 1Q→1


  1. Process 2: 92238U→90234Th+…{}_{92}^{238}U \to {}_{90}^{234}Th + \dots92238​U→90234​Th+…

    • Mass number decreases by 4: 238→234238 \to 234238→234
    • Atomic number decreases by 2: 92→9092 \to 9092→90

    This is alpha decay, since an alpha particle is 24He{}_2^4He24​He

    Hence, P→2P \to 2P→2


  1. Process 3: 83185Bi→82184Pb+…{}_{83}^{185}Bi \to {}_{82}^{184}Pb + \dots83185​Bi→82184​Pb+…

    • Mass number decreases by 1: 185→184185 \to 184185→184
    • Atomic number decreases by 1: 83→8283 \to 8283→82

    This corresponds to proton emission, since a proton is 11H{}_1^1H11​H

    Hence, S→3S \to 3S→3


  1. Process 4: 94239Pu→57140La+…{}_{94}^{239}Pu \to {}_{57}^{140}La + \dots94239​Pu→57140​La+…

    This is splitting of a heavy nucleus into lighter nuclei, so it is fission.

    Hence, R→4R \to 4R→4


  1. Final matching
  • PPP (Alpha decay) →2\to 2→2
  • QQQ (β+\beta^+β+ decay) →1\to 1→1
  • RRR (Fission) →4\to 4→4
  • SSS (Proton emission) →3\to 3→3

So the correct option is: C\boxed{\text{C}}C​


  1. Comparison with stored answer

Stored correct answer: C

Our derived answer: C

So, the derived answer agrees with the stored answer.

PreviousNext

More from Atoms and Nuclei

  • The β-decay process, discovered in around 1900, is basically the decay of a neutron (n). In the laboratory, a proton (p) and an electron (e −) are observed as the decay products of the neutron. Therefore, considering the decay of a…2012 · MCQ
  • The β-decay process, discovered in around 1900, is basically the decay of a neutron (n). In the laboratory, a proton (p) and an electron (e −) are observed as the decay products of the neutron. Therefore, considering the decay of a…2012 · MCQ
  • The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Ao​. The wavelength of the second spectral line in the Balmer series of singly-ionized helium atom is2011 · MCQ
  • To determine the half-life of a radioactive element, a student plots a graph of ln​dtdN(t)​​ versus t. Here, dtdN(t)​ is the rate of radioactive decay at time t. If the number of radioactive… Includes diagram2010 · Numerical
  • The key feature of Bohr's theory of spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton. We will extend this to a general rotational motion to find quantized rotational energy of…2010 · MCQ
  • The key feature of Bohr's theory of spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton. We will extend this to a general rotational motion to find quantized rotational energy of…2010 · MCQ
  • The key feature of Bohr's theory of spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton. We will extend this to a general rotational motion to find quantized rotational energy of…2010 · MCQ
  • When a particle is restricted to move along x-axis between x = 0 and x = a, where a is of nanometer dimension, its energy can take only certain specific values. The allowed energies of the particle moving in such a restricted region,…2009 · MCQ