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Alternating Current question

2025 · Shift 1 · Q47
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Alternating Current question

2025 · Shift 1 · Q47

JEE AdvancedPhysicsAlternating CurrentMCQ+4 / −1

A circuit with an electrical load having impedance ZZZ is connected with an AC source as shown in the diagram. The source voltage varies in time as V(t)=300sin⁡(400t)VV(t)=300 \sin (400 t) \mathrm{V}V(t)=300sin(400t)V, where ttt is time in s . List-I shows various options for the load. The possible currents i(t)i(t)i(t) in the circuit as a function of time are given in List-II.

JEE Advanced 2025 Paper 1 Online Physics - Alternating Current Question 1 English 1

Choose the option that describes the correct match between the entries in List-I to those in ListII.

List–I List–II
(P) JEE Advanced 2025 Paper 1 Online Physics - Alternating Current Question 1 English 2 (1) JEE Advanced 2025 Paper 1 Online Physics - Alternating Current Question 1 English 3
(Q) JEE Advanced 2025 Paper 1 Online Physics - Alternating Current Question 1 English 4 (2) JEE Advanced 2025 Paper 1 Online Physics - Alternating Current Question 1 English 5
(R) JEE Advanced 2025 Paper 1 Online Physics - Alternating Current Question 1 English 6 (3) JEE Advanced 2025 Paper 1 Online Physics - Alternating Current Question 1 English 7
(S) JEE Advanced 2025 Paper 1 Online Physics - Alternating Current Question 1 English 8 (4) JEE Advanced 2025 Paper 1 Online Physics - Alternating Current Question 1 English 9
(5) JEE Advanced 2025 Paper 1 Online Physics - Alternating Current Question 1 English 10
  1. A
    P→3,Q→5,R→2, S→1\mathrm{P} \rightarrow 3, \mathrm{Q} \rightarrow 5, \mathrm{R} \rightarrow 2, \mathrm{~S} \rightarrow 1P→3,Q→5,R→2, S→1
  2. B
    P→1,Q→5,R→2, S→3\mathrm{P} \rightarrow 1, \mathrm{Q} \rightarrow 5, \mathrm{R} \rightarrow 2, \mathrm{~S} \rightarrow 3P→1,Q→5,R→2, S→3
  3. C
    P→3,Q→4,R→2, S→1\mathrm{P} \rightarrow 3, \mathrm{Q} \rightarrow 4, \mathrm{R} \rightarrow 2, \mathrm{~S} \rightarrow 1P→3,Q→4,R→2, S→1
  4. D
    P→1,Q→4,R→2, S→5\mathrm{P} \rightarrow 1, \mathrm{Q} \rightarrow 4, \mathrm{R} \rightarrow 2, \mathrm{~S} \rightarrow 5P→1,Q→4,R→2, S→5
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