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Alternating Current question

2023 · Shift 1 · Q50
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  5. /2023 · Shift 1 · Q50

Alternating Current question

2023 · Shift 1 · Q50

JEE AdvancedPhysicsAlternating CurrentMCQ+3 / −1
A series LCR circuit is connected to a 45sin⁡(ωt)45 \sin (\omega t)45sin(ωt) Volt source. The resonant angular frequency of the circuit is 105 rad s−110^5 ~\mathrm{rad}~ \mathrm{s}^{-1}105 rad s−1 and current amplitude at resonance is I0I_0I0​. When the angular frequency of the source is ω=8×104 rad s−1\omega=8 \times 10^4 ~\mathrm{rad} ~\mathrm{s}^{-1}ω=8×104 rad s−1, the current amplitude in the circuit is 0.05I00.05 I_00.05I0​. If L=50 mHL=50 ~\mathrm{mH}L=50 mH, match each entry in List-I with an appropriate value from List-II and choose the correct option.

List - I List - II
(P) I0I_0I0​ in mA\mathrm{mA}mA (1) 44.4
(Q) The quality factor of the circuit (2) 18
(R) The bandwidth of the circuit in rad s−1\mathrm{rad}~ \mathrm{s}^{-1}rad s−1 (3) 400
(S) The peak power dissipated at resonance in Watt (4) 2250
(5) 500
  1. A
    P→2,Q→3,R→5,S→1P \rightarrow 2, Q \rightarrow 3, R \rightarrow 5, S \rightarrow 1P→2,Q→3,R→5,S→1
  2. B
    P→3,Q→1,R→4,S→2P \rightarrow 3, Q \rightarrow 1, R \rightarrow 4, S \rightarrow 2P→3,Q→1,R→4,S→2
  3. C
    P→4,Q→5,R→3,S→1P \rightarrow 4, Q \rightarrow 5, R \rightarrow 3, S \rightarrow 1P→4,Q→5,R→3,S→1
  4. D
    P→4,Q→2,R→1,S→5P \rightarrow 4, Q \rightarrow 2, R \rightarrow 1, S \rightarrow 5P→4,Q→2,R→1,S→5
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