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Indefinite Integrals question

2012 · Shift 1 · Q32
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  5. /2012 · Shift 1 · Q32

Indefinite Integrals question

2012 · Shift 1 · Q32

JEE AdvancedMathematicsIndefinite IntegralsMCQ+4 / −1
The integral ∫sec⁡2x(sec⁡x+tan⁡x)9/2dx\int \frac{\sec ^2 x}{(\sec x+\tan x)^{9 / 2}} d x∫(secx+tanx)9/2sec2x​dx equals (for some arbitrary constant KKK)
  1. A
    −1(sec⁡x+tan⁡x)11/2{111−17(sec⁡x+tan⁡x)2}+K-\frac{1}{(\sec x+\tan x)^{11 / 2}}\left\{\frac{1}{11}-\frac{1}{7}(\sec x+\tan x)^2\right\}+K−(secx+tanx)11/21​{111​−71​(secx+tanx)2}+K
  2. B
    1(sec⁡x+tan⁡x)11/2{111−17(sec⁡x+tan⁡x)2}+K\frac{1}{(\sec x+\tan x)^{11 / 2}}\left\{\frac{1}{11}-\frac{1}{7}(\sec x+\tan x)^2\right\}+K(secx+tanx)11/21​{111​−71​(secx+tanx)2}+K
  3. C
    −1(sec⁡x+tan⁡x)11/2{111+17(sec⁡x+tan⁡x)2}+K-\frac{1}{(\sec x+\tan x)^{11 / 2}}\left\{\frac{1}{11}+\frac{1}{7}(\sec x+\tan x)^2\right\}+K−(secx+tanx)11/21​{111​+71​(secx+tanx)2}+K
  4. D
    1(sec⁡x+tan⁡x)11/2{111+17(sec⁡x+tan⁡x)2}+K\frac{1}{(\sec x+\tan x)^{11 / 2}}\left\{\frac{1}{11}+\frac{1}{7}(\sec x+\tan x)^2\right\}+K(secx+tanx)11/21​{111​+71​(secx+tanx)2}+K
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