JEE AdvancedMathematicsIndefinite IntegralsMCQ+4 / −1The integral ∫sec2x(secx+tanx)9/2dx\int \frac{\sec ^2 x}{(\sec x+\tan x)^{9 / 2}} d x∫(secx+tanx)9/2sec2xdx equals (for some arbitrary constant KKK)A−1(secx+tanx)11/2{111−17(secx+tanx)2}+K-\frac{1}{(\sec x+\tan x)^{11 / 2}}\left\{\frac{1}{11}-\frac{1}{7}(\sec x+\tan x)^2\right\}+K−(secx+tanx)11/21{111−71(secx+tanx)2}+KB1(secx+tanx)11/2{111−17(secx+tanx)2}+K\frac{1}{(\sec x+\tan x)^{11 / 2}}\left\{\frac{1}{11}-\frac{1}{7}(\sec x+\tan x)^2\right\}+K(secx+tanx)11/21{111−71(secx+tanx)2}+KC−1(secx+tanx)11/2{111+17(secx+tanx)2}+K-\frac{1}{(\sec x+\tan x)^{11 / 2}}\left\{\frac{1}{11}+\frac{1}{7}(\sec x+\tan x)^2\right\}+K−(secx+tanx)11/21{111+71(secx+tanx)2}+KD1(secx+tanx)11/2{111+17(secx+tanx)2}+K\frac{1}{(\sec x+\tan x)^{11 / 2}}\left\{\frac{1}{11}+\frac{1}{7}(\sec x+\tan x)^2\right\}+K(secx+tanx)11/21{111+71(secx+tanx)2}+KAttempt in chatShareNextMore from Indefinite IntegralsLet I=∫e4x+e2x+1exdx,J=∫e−4x+e−2x+1e−xdx. Then for an arbitrary constant C, the value of J−I equals :2008 · MCQ