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Indefinite Integrals question

2008 · Shift 2 · Q33
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  2. /JEE Advanced
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  4. /Indefinite Integrals
  5. /2008 · Shift 2 · Q33

Indefinite Integrals question

2008 · Shift 2 · Q33

JEE AdvancedMathematicsIndefinite IntegralsMCQ+3 / −1
Let I=∫exe4x+e2x+1dx,  J=∫e−xe−4x+e−2x+1dx.I = \int {{{{e^x}} \over {{e^{4x}} + {e^{2x}} + 1}}dx,\,\,J = \int {{{{e^{ - x}}} \over {{e^{ - 4x}} + {e^{ - 2x}} + 1}}dx.} }I=∫e4x+e2x+1ex​dx,J=∫e−4x+e−2x+1e−x​dx. Then for an arbitrary constant CCC, the value of J−IJ -IJ−I equals :
  1. A
    12log⁡(e4x−e2x+1e4x+e2x+1)+C{1 \over 2}\log \left( {{{{e^{4x}} - {e^{2x}} + 1} \over {{e^{4x}} + {e^{2x}} + 1}}} \right) + C21​log(e4x+e2x+1e4x−e2x+1​)+C
  2. B
    12log⁡(e2x+ex+1e2x−ex+1)+C{1 \over 2}\log \left( {{{{e^{2x}} + {e^x} + 1} \over {{e^{2x}} - {e^x} + 1}}} \right) + C21​log(e2x−ex+1e2x+ex+1​)+C
  3. C
    12log⁡(e2x−ex+1e2x+ex+1)+C{1 \over 2}\log \left( {{{{e^{2x}} - {e^x} + 1} \over {{e^{2x}} + {e^x} + 1}}} \right) + C21​log(e2x+ex+1e2x−ex+1​)+C
  4. D
    12log⁡(e4x+e2x+1e4x−e2x+1)+C{1 \over 2}\log \left( {{{{e^{4x}} + {e^{2x}} + 1} \over {{e^{4x}} - {e^{2x}} + 1}}} \right) + C21​log(e4x−e2x+1e4x+e2x+1​)+C
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