JEE AdvancedMathematicsIndefinite IntegralsMCQ+3 / −1Let I=∫exe4x+e2x+1dx, J=∫e−xe−4x+e−2x+1dx.I = \int {{{{e^x}} \over {{e^{4x}} + {e^{2x}} + 1}}dx,\,\,J = \int {{{{e^{ - x}}} \over {{e^{ - 4x}} + {e^{ - 2x}} + 1}}dx.} }I=∫e4x+e2x+1exdx,J=∫e−4x+e−2x+1e−xdx. Then for an arbitrary constant CCC, the value of J−IJ -IJ−I equals :A12log(e4x−e2x+1e4x+e2x+1)+C{1 \over 2}\log \left( {{{{e^{4x}} - {e^{2x}} + 1} \over {{e^{4x}} + {e^{2x}} + 1}}} \right) + C21log(e4x+e2x+1e4x−e2x+1)+CB12log(e2x+ex+1e2x−ex+1)+C{1 \over 2}\log \left( {{{{e^{2x}} + {e^x} + 1} \over {{e^{2x}} - {e^x} + 1}}} \right) + C21log(e2x−ex+1e2x+ex+1)+CC12log(e2x−ex+1e2x+ex+1)+C{1 \over 2}\log \left( {{{{e^{2x}} - {e^x} + 1} \over {{e^{2x}} + {e^x} + 1}}} \right) + C21log(e2x+ex+1e2x−ex+1)+CD12log(e4x+e2x+1e4x−e2x+1)+C{1 \over 2}\log \left( {{{{e^{4x}} + {e^{2x}} + 1} \over {{e^{4x}} - {e^{2x}} + 1}}} \right) + C21log(e4x−e2x+1e4x+e2x+1)+CAttempt in chatSharePreviousMore from Indefinite IntegralsThe integral ∫(secx+tanx)9/2sec2xdx equals (for some arbitrary constant K)2012 · MCQ