Doubts
Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents
Sign in to save progress →
Doubts
Sign in

Complex Numbers question

2017 · Shift 1 · Q21
Guest · try one question or challengeGuest · try one question or challenge
  1. PYQ Library
  2. /JEE Advanced
  3. /Mathematics
  4. /Complex Numbers
  5. /2017 · Shift 1 · Q21

Complex Numbers question

2017 · Shift 1 · Q21

JEE AdvancedMathematicsComplex NumbersMultiple correct+4 / −1
Let a, b, x and y be real numbers such that a −-− b = 1 and y eee 0. If the complex number z = x + iy satisfies Imolimits(az+bz+1)=y{\mathop{\rm Im} olimits} \left( {{{az + b} \over {z + 1}}} \right) = yImolimits(z+1az+b​)=y, then which of the following is(are) possible value(s) of x?
  1. A
    1−1+y21 - \sqrt {1 + {y^2}}1−1+y2​
  2. B
    −1−1−y2- 1 - \sqrt {1 - {y^2}}−1−1−y2​
  3. C
    1+1+y21 + \sqrt {1 + {y^2}}1+1+y2​
  4. D
    −1+1−y2- 1 + \sqrt {1 - {y^2}}−1+1−y2​
PreviousNext

More from Complex Numbers

  • Let a,b∈Randa2+b2e0. Suppose S={Z∈C:Z=a+ibt1​,+∈R,te0}, where i=−1​. Ifz = x + iy and z ∈ S, then (x, y) lies on2016 · Multiple correct
  • For any integer k, let ak​=cos(7kπ​)+isin(7kπ​), where i=−1​. The value of the expression k=1∑3​∣α4k−1​−α4k−2​∣k=1∑12​∣αk+1​−ak​∣​…2015 · Numerical
  • Let zk​=cos(102kπ​)+isin(102kπ​);k=1,2....,9 List-I P. For each zk​= there exits as zj​ such that zk​. zj​ = 1 Q. There exists a k∈{1,2,....,9}…2014 · MCQ
  • Let complex numbers αandα1​ lie on circles (x−x0​)2+(y−y0​)2=r2 and (x−x0​)2+(y−y0​)2=4r2…2013 · MCQ
  • Let ω=23​+i​ and P={ωn:n=1,2,3,…}. Further H1​={z∈C:Rez<21​} and H2​={z∈C:Rez<2−1​}…2013 · Multiple correct
  • Let S=S1​∩S2​∩S3​, where S1​={z∈C:∣z∣<4},S2​={z∈C:Imolimits[1−3​iz−1+3​i​]>0} and S3​={z∈C:Reolimitsz>0}…2013 · MCQ
  • Let S=S1​∩S2​∩S3​, where S1​={z∈C:∣z∣<4},S2​={z∈C:Im[1−3​iz−1+3​i​]>0} and S3​={z∈C:Re(z)>0}…2013 · MCQ
  • Let z be a complex number such that the imaginary part of z is non-zero and a=z2+z+1 is real. Then a cannot take the value2012 · MCQ