- A
- B
- C
- D
View written solutionFree
Correct answer: A
Step-by-step Solution:
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Identify the given equations. The equation of the circle is . Its center is at the origin and its radius is . The equation of the straight line is .
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Set up the coordinates. Let be any point on the given straight line from which tangents are drawn to the circle. Since lies on the line, it must satisfy the line's equation: Let be the midpoint of the chord of contact of the tangents drawn from . We need to find the locus of .
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Find the equation of the chord of contact. The equation of the chord of contact of tangents drawn from an external point to the circle is given by the formula .
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Find the equation of the chord with a given midpoint. The equation of a chord of the circle whose midpoint is is given by the formula . Here, and . So, the equation is:
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Equate the two representations of the chord. Equations (2) and (3) both represent the same line (the chord of contact). Therefore, the coefficients of , , and the constant terms must be proportional. Comparing equation (2), , and equation (3), , we get:
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Express and in terms of and . From the proportionality, we can express and as:
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Use the condition that lies on the line. Substitute the expressions for and into the equation of the line (1):
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Simplify to find the locus. Rearranging the terms, we get:
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Generalize the locus. To find the locus of the midpoint , we replace with :
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Compare with the given options. The derived locus is , which matches option A.
Conclusion
The correct option is A.
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