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Surface Chemistry question

2024 · Shift 2 · Q8
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Surface Chemistry question

2024 · Shift 2 · Q8

JEE AdvancedChemistrySurface ChemistryNumerical+4 / −1
To form a complete monolayer of acetic acid on 1 g1 \mathrm{~g}1 g of charcoal, 100 mL100 \mathrm{~mL}100 mL of 0.5M0.5 \mathrm{M}0.5M acetic acid was used. Some of the acetic acid remained unadsorbed. To neutralize the unadsorbed acetic acid, 40 mL\mathrm{mL}mL of 1MNaOH1 \mathrm{M} \mathrm{NaOH}1MNaOH solution was required. If each molecule of acetic acid occupies P×10−23 m2\mathbf{P} \times 10^{-23} \mathrm{~m}^2P×10−23 m2 surface area on charcoal, the value of P\mathbf{P}P is ‾\underline{\hspace{2cm}}​. [Use given data: Surface area of charcoal =1.5×102 m2 g−1=1.5 \times 10^2 \mathrm{~m}^2 \mathrm{~g}^{-1}=1.5×102 m2 g−1; Avogadro's number (NA)=6.0×1023mol−1]\left(\mathrm{N}_{\mathrm{A}}\right)=6.0 \times 10^{23}\left.\mathrm{mol}^{-1}\right](NA​)=6.0×1023mol−1]
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