Identify the reaction sequence from the practical organic chemistry context

In this standard sequence:

• Aniline is first diazotised to benzene diazonium chloride.
• On treatment with sulfurous acid / sulfur dioxide in presence of copper salts, the diazonium salt gives benzenesulfonyl chloride.
• Benzenesulfonyl chloride then reacts with aniline to form the sulfonamide derivative used in the Hinsberg-type reaction sequence.

Thus, $Q$ is N-phenyl benzenesulfonamide.

Write the molecular formula of $Q$

Benzenesulfonyl chloride has formula: $C_6H_5SO_2Cl$

Reaction with aniline $C_6H_5NH_2$ replaces Cl by $NH(C_6H_5)$: $C_6H_5SO_2Cl + C_6H_5NH_2 \rightarrow C_6H_5SO_2NHC_6H_5 + HCl$

Therefore, $Q = C_{12}H_{11}NO_2S$

Calculate molar mass of $Q$

$M = 12(12) + 11(1) + 14 + 2(16) + 32$ $= 144 + 11 + 14 + 32 + 32$ $= 233$

Calculate percentage of hydrogen

Mass of hydrogen in one mole of $Q$: $= 11$

Hence, $\%H = \frac{11}{233} \times 100$

$\%H = 4.72\% \text{ (approximately)}$

Compare with stored answer

The derived value is: $4.72$

The stored correct answer is $1.30$ to $1.32$, which does not match.

So the stored answer appears inconsistent with the standard reaction/product interpretation.