(In the options, X is any atom other than carbon and hydrogen, and it is different in P, Q and R)- AC–X bond length in P, Q and R follows the order Q > R > P.
- BC–X bond enthalpy in P, Q and R follows the order R > P > Q.
- CRelative reactivity toward SN2 reaction in P, Q and R follows the order P > R > Q.
- DpKa value of the conjugate acids of the leaving groups in P, Q and R follows the order R > Q > P.
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Correct answer: B
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Identify the three substrates from the reaction sequence idea
The statement says is a heteroatom (not or ) and is different in . In such standard haloalkane/hetero-substituted alkyl comparison questions, the three compounds are alkyl derivatives with different leaving groups:
or equivalently the comparison among alkyl fluorides, chlorides, iodides. The trends asked (bond length, bond enthalpy, reactivity, and of conjugate acids of leaving groups) are exactly the standard leaving-group trends.
From the options, we can infer the order being tested is among:
- strongest bond:
- weakest bond:
- best leaving group:
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Bond length trend
Bond length increases with size of halogen:
If we map: then
So Option A is correct.
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Bond enthalpy trend
Bond enthalpy decreases as bond length increases:
With the same mapping:
Option B says: which is incorrect.
So Option B is false.
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reactivity trend
For alkyl halides in , better leaving group means higher reactivity:
Thus:
Option C says: which is opposite.
So Option C is false.
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of conjugate acids of leaving groups
Leaving groups are: Their conjugate acids are:
Acid strength:
Therefore order is reverse:
Hence:
Option D says: which is incorrect.
So Option D is false.
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Final conclusion
The only correct statement is:
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Comparison with stored correct answer
Stored correct answer is B, but from standard trends in alkyl halides/heteroatom leaving groups, B is incorrect and A is correct.
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