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Gaseous State question

2009 · Shift 1 · Q3
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Gaseous State question

2009 · Shift 1 · Q3

JEE AdvancedChemistryGaseous StateMCQ+3 / −1
The term that corrects for the attractive forces present in a real gas in the van der Waals equation is
  1. A
    nbnbnb
  2. B
    an2V2{{a{n^2}} \over {{V^2}}}V2an2​
  3. C
    −an2V2- {{a{n^2}} \over {{V^2}}}−V2an2​
  4. D
    −nb- nb−nb
View written solutionFree

Correct answer: B

  1. Write the van der Waals equation

    For a real gas, the van der Waals equation is (P+an2V2)(V−nb)=nRT\left(P + \frac{a n^2}{V^2}\right)(V-nb)=nRT(P+V2an2​)(V−nb)=nRT

  2. Identify the meaning of each correction term

    • The term nbnbnb corrects for the finite volume of gas molecules.
    • The term an2V2\dfrac{a n^2}{V^2}V2an2​ corrects for intermolecular attractive forces.
  3. Why this pressure correction appears

    In a real gas, attractive forces between molecules reduce the observed pressure compared to an ideal gas. So, to correct the pressure, we add an2V2\frac{a n^2}{V^2}V2an2​ to the measured pressure PPP.

  4. Check the options

    • A: nbnbnb → volume correction, not attraction correction.
    • B: an2V2\dfrac{a n^2}{V^2}V2an2​ → correct, this is the attraction correction term.
    • C: −an2V2-\dfrac{a n^2}{V^2}−V2an2​ → not the term as used in the van der Waals equation.
    • D: −nb-nb−nb → not correct.
  5. Final answer

    The term correcting for attractive forces is an2V2\boxed{\frac{a n^2}{V^2}}V2an2​​ So the correct option is B.

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