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D and F Block Elements question

2009 · Shift 2 · Q16

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JEE Advanced
Chemistry
D and F Block Elements
2009 · Shift 2 · Q16

D and F Block Elements question

2009 · Shift 2 · Q16

JEE AdvancedChemistryD and F Block ElementsNumerical+3 / −1

The oxidation number of Mn in the product of alkaline oxidative fusion of MnO

{}_2

is

\underline{\hspace{2cm}}

.

Numerical answer

View written solutionFree

Correct answer: 6

Identify the reaction mentioned

In alkaline oxidative fusion, manganese dioxide $\text{MnO}_2$ is fused with an alkali in presence of an oxidizing agent (or air), producing manganate.

A common reaction is: $2\text{MnO}_2 + 4\text{KOH} + \text{O}_2 \rightarrow 2\text{K}_2\text{MnO}_4 + 2\text{H}_2\text{O}$

So the product containing Mn is potassium manganate, $\text{K}_2\text{MnO}_4$ .
Find oxidation number of Mn in $\text{K}_2\text{MnO}_4$

Let oxidation number of Mn be $x$ .

We know:
- $\text{K} = +1$
- $\text{O} = -2$
Therefore, for $\text{K}_2\text{MnO}_4$ : $2(+1) + x + 4(-2) = 0$

$2 + x - 8 = 0$

$x - 6 = 0$

$x = +6$
Final answer

The oxidation number of Mn in the product is: $\boxed{6}$

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