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Chemical Kinetics and Nuclear Chemistry question

2022 · Shift 1 · Q15
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Chemical Kinetics and Nuclear Chemistry question

2022 · Shift 1 · Q15

JEE AdvancedChemistryChemical Kinetics and Nuclear ChemistryMCQ+3 / −1

Match the rate expressions in LIST-I for the decomposition of XXX with the corresponding profiles provided in LIST-II. XsX_{\mathrm{s}}Xs​ and k\mathrm{k}k are constants having appropriate units.

List-I List-II
(I) rate =k[X]Xs+[X]=\frac{\mathrm{k}[\mathrm{X}]}{\mathrm{X}_{\mathrm{s}}+[\mathrm{X}]}=Xs​+[X]k[X]​

under all possible initial concentrations of X\mathrm{X}X
(P) JEE Advanced 2022 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 8 English 1
(II) rate =k[X]Xs+[X]=\frac{k[X]}{X_{s}+[X]}=Xs​+[X]k[X]​

where initial concentrations of XXX are much less than XsX_{s}Xs​
(Q) JEE Advanced 2022 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 8 English 2
(III) rate =k[X]Xs+[X]=\frac{k[X]}{X_{s}+[X]}=Xs​+[X]k[X]​

where initial concentrations of XXX are much higher than XsX_{s}Xs​
(R) JEE Advanced 2022 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 8 English 3
(IV) rate =k[X]2Xs+[X]=\frac{k[X]^{2}}{X_{s}+[X]}=Xs​+[X]k[X]2​

where initial concentration of XXX is

much higher than Xs\mathrm{X}_{\mathrm{s}}Xs​
(S) JEE Advanced 2022 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 8 English 4
(T) JEE Advanced 2022 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 8 English 5

  1. A
    I→P\mathrm{I} \rightarrow \mathrm{P}I→P; II →\rightarrow→ Q; III →S\rightarrow \mathrm{S}→S; IV →T\rightarrow \mathrm{T}→T
  2. B
    I→R\mathrm{I} \rightarrow \mathrm{R}I→R; II →S\rightarrow \mathrm{S}→S; III →S\rightarrow \mathrm{S}→S; IV →T\rightarrow \mathrm{T}→T
  3. C
    I→P\mathrm{I} \rightarrow \mathrm{P}I→P; II →\rightarrow→ Q; III →\rightarrow→ Q; IV →\rightarrow→ R
  4. D
    I→R\mathrm{I} \rightarrow \mathrm{R}I→R; II →S\rightarrow \mathrm{S}→S; III →\rightarrow→ Q; IV →R\rightarrow \mathrm{R}→R
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