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Wave Optics question

2019 · Q143
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Wave Optics question

2019 · Q143

NEETPhysicsWave OpticsMCQ+4 / −1
In a double slit experiment, when light of wavelength 400 nm was used, the angular width of the first minima formed on a screen placed 1m away, was found to be 0.2o. What will be the angular width of the first minima, (μ\muμwater = 4/3) if the entire experimental apparatus is immersed in water?
  1. A
    0.15o
  2. B
    0.05o
  3. C
    0.1o
  4. D
    0.266o
View written solutionFree

Correct answer: A

Angular fringe width (in air) θ\theta θair = βD{\beta \over D}Dβ​

Angular Fringe width (in water)

θ\theta θw = βμD=θairμ{\beta \over {\mu D}} = {{{\theta _{air}}} \over \mu }μDβ​=μθair​​

= 0.2∘43{{0.2^\circ } \over {{4 \over 3}}}34​0.2∘​ = 0.15o

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