NEETPhysicsSemiconductor ElectronicsMCQ+4 / −1
In the given figure, a diode D is connected to an external resistance R = 100 and an e.m.f. of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current in the citcuit will be
- A20 mA
- B35 mA
- C30 mA
- D40 mA
View written solutionFree
Correct answer: C
Potential difference across resistance R
= 3.5 – 0.5 = 3.0 V
Current in circuit, I = V/R = 3/100 = 30 mA
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