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Semiconductor Electronics question

2011 · Q84
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Semiconductor Electronics question

2011 · Q84

NEETPhysicsSemiconductor ElectronicsMCQ+4 / −1
A Zener diode, having breakdown voltage equal to 15 V, is used in a voltage regulator circuit shown in figure. The current through the diode is

AIPMT 2011 Mains Physics - Semiconductor Electronics Question 80 English
  1. A
    5 mA
  2. B
    10 mA
  3. C
    15 mA
  4. D
    20 mA
View written solutionFree

Correct answer: A

Voltage across 250 Ω resistance = 20 V – 15 V = 5 V

Now current through 250 Ω\Omega Ω resistance: 5/250 = 20 mA

If voltage across load resistance 1 kΩ\Omega Ω is 15 V, then

current through 1 kΩ is 15/1000 = 15 mA

The current through the zener diode is

= Current through 250 Ω\Omega Ω resistance – Current through 1 kΩ\Omega Ω resistance.

= 20 - 15

= 5 mA

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