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Rotational Motion question

2012 · Q161
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Rotational Motion question

2012 · Q161

NEETPhysicsRotational MotionMCQ+4 / −1
A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless road. If the banking angle is 45o, the speed of the car is
  1. A
    20 m s−-−1
  2. B
    30 m s−-−1
  3. C
    5 m s−-−1
  4. D
    10 m s−-−1
View written solutionFree

Correct answer: B

Here, m = 1000 kg, R = 90 m, θ\theta θ = 45°

For banking, tan⁡θ=v2Rg\tan \theta = {{{v^2}} \over {Rg}}tanθ=Rgv2​

⇒v=Rgtan⁡θ=90×10×tan⁡45o=30 ms−1 \Rightarrow v = \sqrt {Rg\tan \theta } = \sqrt {90 \times 10 \times \tan {{45}^o}} = 30\,m{s^{ - 1}}⇒v=Rgtanθ​=90×10×tan45o​=30ms−1

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