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Rotational Motion question

2002 · Q158
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Rotational Motion question

2002 · Q158

NEETPhysicsRotational MotionMCQ+4 / −1
A point P consider at contact point of a wheel on ground which rolls on ground without slipping then value of displacement of point P when wheel completes half of rotation (if radius of wheel is 1 m)
  1. A
    2 m
  2. B
    π2+4m\sqrt {{\pi ^2} + 4} mπ2+4​m
  3. C
    π m\pi \,mπm
  4. D
    π2+2 m\sqrt {{\pi ^2} + 2} \,mπ2+2​m
View written solutionFree

Correct answer: B

AIPMT 2002 Physics - Rotational Motion Question 30 English Explanation
In half rotation point P has moved horizontally.

πd2=πr=π×1m=π m{{\pi d} \over 2} = \pi r = \pi \times 1m = \pi \,m2πd​=πr=π×1m=πm   [∵radius=1m]\left[ \because {radius = 1m} \right][∵radius=1m]

In the same time, it has moved vertically a distance which is equal to its diameter = 2 m.

∴\therefore∴ Displacement of P = π2+22=π2+4\sqrt {{\pi ^2} + {2^2}} = \sqrt {{\pi ^2} + 4} π2+22​=π2+4​ m

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